2q^2+11qd-63d^2=0

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Solution for 2q^2+11qd-63d^2=0 equation:


Simplifying
2q2 + 11qd + -63d2 = 0

Reorder the terms:
11dq + -63d2 + 2q2 = 0

Solving
11dq + -63d2 + 2q2 = 0

Solving for variable 'd'.

Factor a trinomial.
(-9d + -1q)(7d + -2q) = 0

Subproblem 1

Set the factor '(-9d + -1q)' equal to zero and attempt to solve: Simplifying -9d + -1q = 0 Solving -9d + -1q = 0 Move all terms containing d to the left, all other terms to the right. Add 'q' to each side of the equation. -9d + -1q + q = 0 + q Combine like terms: -1q + q = 0 -9d + 0 = 0 + q -9d = 0 + q Remove the zero: -9d = q Divide each side by '-9'. d = -0.1111111111q Simplifying d = -0.1111111111q

Subproblem 2

Set the factor '(7d + -2q)' equal to zero and attempt to solve: Simplifying 7d + -2q = 0 Solving 7d + -2q = 0 Move all terms containing d to the left, all other terms to the right. Add '2q' to each side of the equation. 7d + -2q + 2q = 0 + 2q Combine like terms: -2q + 2q = 0 7d + 0 = 0 + 2q 7d = 0 + 2q Remove the zero: 7d = 2q Divide each side by '7'. d = 0.2857142857q Simplifying d = 0.2857142857q

Solution

d = {-0.1111111111q, 0.2857142857q}

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